Python讲解之对象转XML方法详解

本文实例讲述了Python实现对象转换为xml的方法。分享给大家供大家参考，具体如下：

# -*- coding:UTF-8 -*-
'''''
Created on 2010-4-20
@author: 忧里修斯
'''
import xml.etree.ElementTree as ET
import xml.dom.minidom as minidom
from addrbook.domain import Person
class Converter(object):
 '''''
 实现Python对象与xml之间的相互转换
 '''
 root = None#根节点
 def __init__(self):
 pass
 @staticmethod
 def createRoot(rootTag):
 '''''
 创建根节点
 '''
 root = ET.Element(rootTag)
 return root
 @staticmethod
 def getXmlString(element,defaultEncoding='utf-8'):
 '''''
 根据节点返回格式化的xml字符串
 '''
 try:
 rough_string = ET.tostring(element, defaultEncoding)
 reparsed = minidom.parseString(rough_string)
 return reparsed.toprettyxml(indent=" " , encoding=defaultEncoding)
 except:
 print 'getXmlString:传入的节点不能正确转换为xml，请检查传入的节点是否正确'
 return ''
 @staticmethod
 def classToElements(classobj,rootTag=None):
 '''''
 根据传入的对象的实例，根据对象的属性生成节点，返回由节点组成的列表
 classobj：对象的实例
 rootTag：根节点名称
 '''
 attrs = None#保存对象的属性集
 elelist = []#节点列表
 try:
 attrs = classobj.__dict__.keys()#获取该对象的所有属性(即成员变量)
 except:
 print 'classToElements:传入的对象非法，不能正确获取对象的属性'
 if attrs != None and len(attrs) > 0:#属性存在
 for attr in attrs:
 attrvalue = getattr(classobj, attr)#属性值
 #属性节点
 attrE = ET.Element(attr)
 attrE.text = attrvalue
 #加入节点列表
 elelist.append(attrE)
 return elelist
 @staticmethod
 def classToXML(classobj,rootTag=None):
 '''''
 Python自定义模型类转换成xml，转换成功返回的是xml根节点，否则返回None
 classobj：对象的实例
 rootTag：根节点名称
 '''
 try:
 classname = classobj.__class__.__name__ #类名
 if rootTag != None:
 root = Converter.createRoot(rootTag)
 else:
 root = Converter.createRoot(classname)
 elelist = Converter.classToElements(classobj, rootTag)
 for ele in elelist:
 root.append(ele)
 return root
 except:
 print 'classToXML:转换出错，请检查的传入的对象是否正确'
 return None
 @staticmethod
 def collectionToXML(listobj,rootTag='list'):
 '''''
 集合（列表、元组、字典）转换为xml，转换成功返回的是xml根节点，否则返回None
 '''
 try:
 classname = listobj.__class__.__name__ #类名
 root = Converter.createRoot(rootTag)
 if isinstance(listobj, list) or isinstance(listobj, tuple):#列表或元组
 if len(listobj) >= 0:
 for obj in listobj:#迭代列表中的对象
 itemE = Converter.classToXML(obj)
 root.append(itemE)
 elif isinstance(listobj, dict):#字典
 if len(listobj) >= 0:
 for key in listobj:#迭代字典中的对象
 obj = listobj[key]
 itemE = Converter.classToXML(obj)
 itemE.set('key', key)
 root.append(itemE)
 else:
 print 'listToXML：转换错误，传入的对象：'+classname+'不是集合类型'
 return root
 except:
 print 'collectionToXML：转换错误，集合转换成xml失败'
 return None
if __name__ == '__main__':
 p1 = Person('dredfsam','男','133665')
 p2 = Person('dream','女','r')
 p3 = Person('得分','男','sdf')
 personList = {}
 personList['p1']= p1
 personList['p2']= p2
 personList['p3']= p3
# personList.append(p1)
# personList.append(p2)
# personList.append(p3)
 root = Converter.collectionToXML(personList)
 print Converter.getXmlString(root)
# plist = (p1,p2,p3)#{'name':'sdf'}
# print type(plist)
# print type(plist),isinstance(plist, list)